\documentclass[12pt]{report} \usepackage{multicol} % \ilf is inline formula in displaystyle \newcommand{\ilf}[1]{$\displaystyle #1 $} \renewcommand{\today}{October 28, 2000} \pagestyle{empty} \begin{document} \begin{center}{\bf Math 1312} --- {\bf Worksheet \# 2}\\ {\bfseries\itshape Taylor Series} \end{center} \medskip\hrulefill\\ \noindent Find the Taylor series with center $x_0$ of the functions $f(x)$ below, and compute their radii of convergence. \begin{multicols}{2} \begin{enumerate} \item\ilf{f(x)=\frac{1}{x+1}\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{1}{x+4}\quad x_0=2}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{1}{x^2+4}\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{1}{x^2-2x+4}\quad x_0=1}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{x-5}{x^3-1}\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\cosh x\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\ln x\quad x_0=3}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{1}{\sqrt{x+1}}\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\frac{1}{\sqrt{x+1}}\quad x_0=2}\vspace{.1\baselineskip} \item\ilf{f(x)=\sqrt{x^2+4}\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\sin (x^2)\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\arcsin(x)\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\arctan(x^2)\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=x\arctan(x^2)\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\int e^{-x^2}\,dx\quad x_0=0}\vspace{.1\baselineskip} \item\ilf{f(x)=\int\frac{\sin x}{x}\,dx\quad x_0=0}\vspace{.1\baselineskip} \end{enumerate} \end{multicols} \vspace*{\fill} \vspace*{\fill} \flushright \tiny Update: January 13, 2001 \end{document}