HelmutKnaust at 00:27, 30 August 2025

2025-08-30T00:27:03Z

HelmutKnaust: Created page with "'''Problem 1.''' Let $A$ and $B$ be two non-empty sets that are bounded from above. Show: If $\sup A < \sup B$, then $B$ contains an element that is an upper bound of $A$. ''..."

2025-08-30T00:24:11Z

Created page with "'''Problem 1.''' Let $A$ and $B$ be two non-empty sets that are bounded from above. Show: If $\sup A < \sup B$, then $B$ contains an element that is an upper bound of $A$. ''..."

New page

'''Problem 1.''' Let $A$ and $B$ be two non-empty sets that are bounded from above. Show: If $\sup A < \sup B$, then $B$ contains an element that is an upper bound of $A$.

'''Problem 2.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ and $t$ both are suprema of $A$, then $s=t$. (This shows that a set can have at most one supremum.)

'''Problem 3.''' Suppose that every non-empty set that is bounded from above has a supremum. Show that then every non-empty set that is bounded form below has an infimum.

'''Problem 4.''' A real number $m$ is called maximum of the set $A\subseteq\mathbb{R}$, if $m\in A$ and $m\geq a$ for all $a\in A$.
# Show: If $m$ is the maximum of $A$, then $m$ is also the supremum of $A$.
# Let $A=\{x\in\mathbb{Q}\ |\ x^2\leq 5\}$. Show that A is bounded from above, but that $A$ has no maximum.

'''Problem 5.''' Show that the ''Nested Interval Property'' together with the ''Archimedean Principle'' implies the ''Axiom of Completeness''.

@@ Line 3: / Line 3: @@
 '''Problem 2.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ and $t$ both are suprema of $A$, then $s=t$. (This shows that a set can have at most one supremum.)
-'''Problem 3.''' Suppose that every non-empty set that is bounded from above has a supremum. Show that then every non-empty set that is bounded form below has an infimum.
+'''Problem 3.''' (1) Give a definition for the ''infimum'' of a set of real numbers. (2) Suppose that every non-empty set that is bounded from above has a supremum. Show that then every non-empty set that is bounded from below has an infimum.
 '''Problem 4.''' A real number $m$ is called maximum of the set $A\subseteq\mathbb{R}$, if $m\in A$ and $m\geq a$ for all $a\in A$.

CRN 10459: HW 1 - Revision history

HelmutKnaust at 00:27, 30 August 2025

HelmutKnaust: Created page with "'''Problem 1.''' Let $A$ and $B$ be two non-empty sets that are bounded from above. Show: If $\sup A < \sup B$, then $B$ contains an element that is an upper bound of $A$. ''..."