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		<title>CRN 11982: HW 1 - Revision history</title>
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		<updated>2026-05-05T00:23:04Z</updated>
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		<id>http://helmut.knaust.info/mediawiki/index.php?title=CRN_11982:_HW_1&amp;diff=1191&amp;oldid=prev</id>
		<title>HelmutKnaust at 14:34, 27 August 2014</title>
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				<updated>2014-08-27T14:34:27Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;table class='diff diff-contentalign-left'&gt;
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			&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;← Older revision&lt;/td&gt;
			&lt;td colspan='2' style=&quot;background-color: white; color:black;&quot;&gt;Revision as of 14:34, 27 August 2014&lt;/td&gt;
			&lt;/tr&gt;&lt;tr&gt;&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot;&gt;Line 5:&lt;/td&gt;
&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot;&gt;Line 5:&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 3.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ and $t$ both are suprema of $A$, then $s=t$. (Suprema are unique.)&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 3.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ and $t$ both are suprema of $A$, then $s=t$. (Suprema are unique.)&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;−&lt;/td&gt;&lt;td style=&quot;background: #ffa; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 4.''' A real number $m&lt;del class=&quot;diffchange diffchange-inline&quot;&gt;\in\mathbb{R}&lt;/del&gt;$ is called &lt;del class=&quot;diffchange diffchange-inline&quot;&gt;the &lt;/del&gt;maximum of the set $A\subseteq\mathbb{R}$, if $m\in A$ and $m\geq a$ for all $a\in A$.&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;background: #cfc; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 4.''' A real number $m$ is called maximum of the set $A\subseteq\mathbb{R}$, if $m\in A$ and $m\geq a$ for all $a\in A$.&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;# Show: If $m$ is the maximum of $A$, then $m$ is also the supremum of $A$.&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;# Show: If $m$ is the maximum of $A$, then $m$ is also the supremum of $A$.&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;# Let $A=\{x\in\mathbb{Q}\ |\ x^2\leq 5\}$. Show that A is bounded from above, but that $A$ has no maximum. &amp;#160;&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;# Let $A=\{x\in\mathbb{Q}\ |\ x^2\leq 5\}$. Show that A is bounded from above, but that $A$ has no maximum. &amp;#160;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 5.''' Show that the ''Nested Interval Property'' together with the ''Archimedean Principle'' implies the ''Axiom of Completeness''.&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt;&amp;#160;&lt;/td&gt;&lt;td style=&quot;background: #eee; color:black; font-size: smaller;&quot;&gt;&lt;div&gt;'''Problem 5.''' Show that the ''Nested Interval Property'' together with the ''Archimedean Principle'' implies the ''Axiom of Completeness''.&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;</summary>
		<author><name>HelmutKnaust</name></author>	</entry>

	<entry>
		<id>http://helmut.knaust.info/mediawiki/index.php?title=CRN_11982:_HW_1&amp;diff=1190&amp;oldid=prev</id>
		<title>HelmutKnaust: Created page with &quot;'''Problem 1.''' Exercise 1.3.2.  '''Problem 2.''' Exercise 1.3.3(a)(b).  '''Problem 3.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ ...&quot;</title>
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				<updated>2014-08-27T14:33:55Z</updated>
		
		<summary type="html">&lt;p&gt;Created page with &amp;quot;&amp;#039;&amp;#039;&amp;#039;Problem 1.&amp;#039;&amp;#039;&amp;#039; Exercise 1.3.2.  &amp;#039;&amp;#039;&amp;#039;Problem 2.&amp;#039;&amp;#039;&amp;#039; Exercise 1.3.3(a)(b).  &amp;#039;&amp;#039;&amp;#039;Problem 3.&amp;#039;&amp;#039;&amp;#039; Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ ...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;'''Problem 1.''' Exercise 1.3.2.&lt;br /&gt;
&lt;br /&gt;
'''Problem 2.''' Exercise 1.3.3(a)(b).&lt;br /&gt;
&lt;br /&gt;
'''Problem 3.''' Let $A$ be a non-empty set of real numbers that is bounded from above. Show: If $s$ and $t$ both are suprema of $A$, then $s=t$. (Suprema are unique.)&lt;br /&gt;
&lt;br /&gt;
'''Problem 4.''' A real number $m\in\mathbb{R}$ is called the maximum of the set $A\subseteq\mathbb{R}$, if $m\in A$ and $m\geq a$ for all $a\in A$.&lt;br /&gt;
# Show: If $m$ is the maximum of $A$, then $m$ is also the supremum of $A$.&lt;br /&gt;
# Let $A=\{x\in\mathbb{Q}\ |\ x^2\leq 5\}$. Show that A is bounded from above, but that $A$ has no maximum. &lt;br /&gt;
&lt;br /&gt;
'''Problem 5.''' Show that the ''Nested Interval Property'' together with the ''Archimedean Principle'' implies the ''Axiom of Completeness''.&lt;/div&gt;</summary>
		<author><name>HelmutKnaust</name></author>	</entry>

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