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CRN 11378: HW 5

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'''Problem 24.''' A function f:RR is called ''bounded'' if there is an M>0 such that |f(x)|M for all xR.  
 
'''Problem 24.''' A function f:RR is called ''bounded'' if there is an M>0 such that |f(x)|M for all xR.  
 
#Let f,g:RR be two bounded functions that are uniformly continuous on R. Show that fg is uniformly continuous on R.
 
#Let f,g:RR be two bounded functions that are uniformly continuous on R. Show that fg is uniformly continuous on R.
#Show that the result fails without the boundedness condition.
+
#Show that the result may fail without the boundedness condition.

Revision as of 11:29, 5 November 2019

Problem 21. Let the function f:RR be given by f(x)=3x.

  1. Show that f is continuous at 0.
  2. Show that f is continuous at any x00. (The identity a3b3=(ab)(a2+ab+b2) will be helpful.)

Problem 22. Assume f:RR is continuous on R. Show that {xR | f(x)=0} is a closed set.

Problem 23. Let c0. Assume f:RR satisfies |f(x)f(y)|c|xy| for all x,yR.

  1. Show that f is uniformly continuous on R.
  2. Now assume that 0<c<1. Show that there is an xR such that f(x)=x. (Hint: for any yR look at the sequence y,f(y),f(f(y)),f(f(f(y))).
  3. Show that the result in 2. above may fail if c=1.

Problem 24. A function f:RR is called bounded if there is an M>0 such that |f(x)|M for all xR.

  1. Let f,g:RR be two bounded functions that are uniformly continuous on R. Show that fg is uniformly continuous on R.
  2. Show that the result may fail without the boundedness condition.
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