The problems are due on September 11.
Problem 1. Show that is irrational.
Problem 2.
A set A of real numbers is called bounded, if there
are , so that
for all
. Show that
the following statements are equivalent:
Problem 3. Let
. Show that A is bounded from above in
, but has no least upper bound in
.
Hint. One of the steps in the proof is to show the following: If and r>0, choose a rational number q such that 0<q<1 and
. Show that
.
Problem 4. Let A be a non-empty set, which is bounded from above. Show: If , then for all
, there is an
with
.
Problem 5. Prove the correct statement, and give a counterexample to the incorrect one: