The problems are due on September 11.
Problem 1. Show that is irrational.
Problem 2. A set A of real numbers is called bounded, if there are , so that for all . Show that the following statements are equivalent:
Problem 3. Let . Show that A is bounded from above in , but has no least upper bound in .
Hint. One of the steps in the proof is to show the following: If and r>0, choose a rational number q such that 0<q<1 and . Show that .
Problem 4. Let A be a non-empty set, which is bounded from above. Show: If , then for all , there is an with .
Problem 5. Prove the correct statement, and give a counterexample to the incorrect one: