Math 4111
Test 3
Spring 1996



No books, notes etc. are permitted.
Show all your work! Box in your answers!
The test has 7 problems on 4 pages.
Read the problems carefully!

Problem 1 (25 points)   Compute the derivative of the following functions. You need not simplify your answers!
1.
$f(x)=x^5-3x^3+2x^2-\sqrt{2}x+2$
2.
$\displaystyle f(x)=[\sin(x)]^2 \cdot \cos(x) $
3.
$\displaystyle f(x)=\frac{x^2 \cos(2x)}{x^3+e^{-x}} $
4.
$\displaystyle f(x)=\log_4(x) $
5.
$\displaystyle f(x)=\arcsin(\frac{1}{x^2}) $

Problem 2 (15 points)  
1.
Find the first three derivatives of $\displaystyle f(x)=2^{(2x-3)} $.
2.
Find the 100th derivative of $\displaystyle f(x)=2^{(2x-3)} $.

Problem 3 (10 points)   Find an equation for the tangent line of $\displaystyle g(x)=\frac{x^2+5}{x-5} $ at x=0.

Problem 4 (10 points)   Let $\displaystyle B(t)=P(t)\cdot(1.05)^{20-t} $. Given that P(8)=120 and P'(8)=6, find B'(8).

Problem 5 (15 points)   A 300 feet tall hotel has an elevator on the outside of the building. You are standing by a window 100 feet above the ground and 150 feet away from the hotel, and the elevator descends from the top of the hotel at a constant speed of 20 feet per second, starting at time t=0, where t is measured in seconds. Let $\theta$ be the angle between the line of your horizon and your line of sight of the elevator.












1.
Find a formula for h(t), the elevator's height above ground, as it descends from the top of the hotel.
2.
Express $\theta$ as a function of time t.
3.
If the rate of change of $\theta$ with respect to time t is a measure of how fast the elevator appears to you to be moving, at what height will the elevator be when it appears to be moving the fastest?

Problem 6 (15 points)   Find the quantity $\displaystyle \frac{dy}{dx} $ at the point (8,8) on the curve

x2/3+y2/3=8.

Problem 7 (10 points)   A spherical cell is growing at a constant rate of $250 \mu m^3$ per day. At what rate is its radius increasing when the radius r is $10 \mu m$? (The volume V of a sphere with radius r is given by $\displaystyle V=\frac{4}{3}\pi r^3 $.)



Helmut Knaust
1999-02-02